Алгебра: Помогите решить номера..

Решите задачу:

$1.\\a)1.5 \sqrt{0.36}+ \frac{1}{2} \sqrt{196}=1.5*0.6+0.5*14 =0.9+7=7.9\\b)1.5-7 \sqrt{ \frac{25}{49} } =1.5-7* \frac{5}{7} =1.5-5=-3.5\\c)(2 \sqrt{1.5} )^2=4*1.5=6\\2.\\a) \sqrt{0.36*25}=0.6*5=3\\b) \sqrt{8} * \sqrt{18} = \sqrt{64}=8\\c) \sqrt{2^4*5^2}=2^2*5=20\\d) \frac{ \sqrt{27} }{ \sqrt{3} } = \sqrt{ \frac{27}{3} } = \sqrt{9}=3\\3.\\a)x^2=0.64\\ |{ {{x=-0.8} \atop {x=0.8}} \right. \\OTBET:б0.8\\b)x^2=17\\|{ {{x=- \sqrt{17} } \atop {x= \sqrt{17} }} \right. \\OTBET:б \sqrt{17}$
$6.\\ \sqrt{x-2}=1|^2\\x-2=1 \\x=3\\OTBET:3$
$4.\\y^3 \sqrt{4y^2}=2y^4\\7a \sqrt{\frac{16}{a^2}} ,a\ \textless \ 0......7a \frac{4}{|a|}$
$5.\\6.1\ \textless \ \sqrt{38} \ \textless \ 6.2$