ОДЗ : x - 3 > 0 ⇒ x > 3
-2\\\\x-3<(\frac{1}{6})^{-2}\\\\x-3<36\\\\x<39\\\\x\in(-\infty;39)" alt="log_{\frac{1}{6} }(x-3)>-2\\\\x-3<(\frac{1}{6})^{-2}\\\\x-3<36\\\\x<39\\\\x\in(-\infty;39)" align="absmiddle" class="latex-formula">
Ответ : x ∈ (3 ; 39)